2[4z-1]=3[z+h]

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Solution for 2[4z-1]=3[z+h] equation:


Simplifying
2[4z + -1] = 3[z + h]

Reorder the terms:
2[-1 + 4z] = 3[z + h]
[-1 * 2 + 4z * 2] = 3[z + h]
[-2 + 8z] = 3[z + h]

Reorder the terms:
-2 + 8z = 3[h + z]
-2 + 8z = [h * 3 + z * 3]
-2 + 8z = [3h + 3z]

Solving
-2 + 8z = 3h + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-2 + 8z + -3z = 3h + 3z + -3z

Combine like terms: 8z + -3z = 5z
-2 + 5z = 3h + 3z + -3z

Combine like terms: 3z + -3z = 0
-2 + 5z = 3h + 0
-2 + 5z = 3h

Add '2' to each side of the equation.
-2 + 2 + 5z = 2 + 3h

Combine like terms: -2 + 2 = 0
0 + 5z = 2 + 3h
5z = 2 + 3h

Divide each side by '5'.
z = 0.4 + 0.6h

Simplifying
z = 0.4 + 0.6h

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